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Originally Posted by teh rulez
The Bear and the Maiden Fair - lovers. Only win if both survive till the end (regardless of whether it's the Lions or the Inn who win the rest of the game). Can communicate at night. The Bear, being a Werebear, kills one person a night as long as the the Maiden is alive. If one dies, the remaining lover then chooses to help the side that did not kill their lover (that is, becomes effectively an ordo if they're night killed, or cobbler if they're lynched).
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Could our dear moddesses clarify the winning conditions? It seems all players are not interpreting them the same way...
So the lions win now if there are them and two non-lions/innocents/ordos/villagers left? Which of those and with what kind of definition?
What is the Bear and what is the Maiden - and do their status in regards to counting the result change somehow if one of them dies?
The rules say that in case of one going down the remaining lover "effectively becomes" an ordo or a cobbler. Those both are normally counted as "non-lions" and thus someone whose numbers are counted for the village. But what does it mean they "become" it? Isn't the maiden a non-lion already for counting purposes?
To put it plainly. How many normal villagers (ordos and/or gifteds) we need to have to win a) if both the Bear and the maiden are also alive, b) if of the lovers only the maiden is alive, c) if of the lovers only the Bear is alive?
EDIT:
HAHA. Sorry the bad phrasing: the plain question of course is: how many normal villagers will lose the game... Naturally we need to kill all lions to win, but at which numbers we lose (presuming there are two lions alive)?